QNT/351

QNT/351.

Question 1

Save your time - order a paper!

Get your paper written from scratch within the tight deadline. Our service is a reliable solution to all your troubles. Place an order on any task and we will take care of it. You won’t have to worry about the quality and deadlines

Order Paper Now

Last week we discussed the one sample hypothesis test. This week we will discuss ANOVA. The ANOVA allows us to test the mean between  two or more groups.

 Teachers Example, I have five pizza delivery areas and I want to know if the average sales per run is different in one area than any of the other areas.

H0: There is no significant difference in the sales per run between the delivery areas

H1: There is a significant difference in the sales per run between the delivery areas

Notice how the hypothesis is very simple. There is a difference or there is not a difference. Again, we will use MegaStat. You cannot calculate ANOVA by hand.

Just put your own sales for each area in a column and click the Megastat menu, select analysis of variance, and highlight your data and click enter. Check your p-value. Interpret.

Here is the teachers example :

      Area 1    Area 2     Area 3   Area 4    Area 5

 $  45.00  $  13.00  $  12.00  $  34.00  $  37.00

 $  34.00  $  24.00  $  37.00  $  25.00  $  22.00

 $  36.00  $  34.00  $  27.00  $  23.00  $  32.00

 $  45.00  $  23.00  $  17.00  $  36.00  $  42.00

 $  53.00  $  32.00  $  28.00  $  23.00  $  35.00

 $   43.00  $  21.00  $  39.00  $  35.00  $  37.00

 $  45.00  $  23.00  $  35.00  $  45.00  $  28.00

 $  65.00  $  24.00  $  26.00  $  34.00  $  13.00

 $  32.00  $  37.00  $  45.00  $  23.00  $  24.00

 $  30.00  $  45.00  $  27.00  $  53.00  $  15.00

 $  40.00  $  32.00  $  34.00  $  29.00  $  63.00

 $  23.00  $  34.00  $  16.00  $  28.00  $  35.00

             

One factor ANOVA           

             

  Mean  n  Std. Dev       

32.45  40.917  12  11.1719  Area 1     

32.45  28.500  12  8.6707  Area 2     

32.45  28.583  12  9.9951  Area 3     

32.45  32.333  12  9.3355  Area 4     

32.45  31.917  12  13.3448  Area 5     

  32.450  60  11.2347  Total     

             

ANOVA table             

Source  SS    df  MS  F    p-value 

Treatment  1,230.4333  4  307.60833  2.72  .0386 

Error  6,216.4167  55  113.02576       

Total  7,446.8500  59         

             

The p-value is less than .05 so I do not reject the null

QNT/351

 
"If this is not the paper you were searching for, you can order your 100% plagiarism free, professional written paper now!"

"Do you have an upcoming essay or assignment due?


Get any topic done in as little as 6 hours

If yes Order Similar Paper

All of our assignments are originally produced, unique, and free of plagiarism.