Given two numbers a and b, the least common multiple (lcm) of a and b is the smallest number m such that both a and b are factors of m. For example, lcm(15, 21) = 105 because it is the smallest number that has both 15 and 21 as factors.
Formally, we will work with the following decision problem:
LCM = {a, b, m | lcm(a, b) = m}
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Order Paper Now(a) Explain why the following algorithm that decides LCM does not run in polynomial time:
a) Check if m is a multiple of a and b; if not reject a, b, m
b) For i = 1, 2, . . . , m − 1 do:
i. If i is a multiple of a and b, a multiple smaller than m was found.
Reject a, b, m.
c) If it reached the end of the loop without finding a multiple less than m, accept a, b, m.
(b) Prove that LCM ∈ P.
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